document.write( "Question 691461: Eduardo created a metal containing 35% gold by combining two other metals. One of these other metals weighed 2 kg and contained 15% gold. If the other weighed 8kg then what percent of it was gold?\r
\n" ); document.write( "\n" ); document.write( "I believe I would set up an equation .35(x + .15) = 2(.15) +8x where x is % of gold in metal 2, but I don't know if that's right, or where to go from there
\n" ); document.write( "

Algebra.Com's Answer #426712 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Eduardo created a metal containing 35% gold by combining two other metals. One of these other metals weighed 2 kg and contained 15% gold. If the other weighed 8kg then what percent4 of it was gold?
\n" ); document.write( "-----
\n" ); document.write( "Equation:
\n" ); document.write( "gold + gold = gold
\n" ); document.write( "0.15*2 + x(8) = 0.35(2+8)
\n" ); document.write( "-------
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "15*2 + 100x*8 = 35*2 + 35*8
\n" ); document.write( "---
\n" ); document.write( "30 + 800x = 70 + 280
\n" ); document.write( "800x = 320
\n" ); document.write( "x = 32/80 = 4/10 = 40%
\n" ); document.write( "---
\n" ); document.write( "Cheers,
\n" ); document.write( "stan H.
\n" ); document.write( "==============
\n" ); document.write( "
\n" );