document.write( "Question 691455: how do I find the Focus, Equation of the Directrix, and the equation of the axis of symmetry from the equation
\n" ); document.write( "x=(1/16)(y-7)^2-5
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Algebra.Com's Answer #426705 by stanbon(75887)\"\" \"About 
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how do I find the Focus, Equation of the Directrix, and the equation of the axis of symmetry from the equation
\n" ); document.write( "x=(1/16)(y-7)^2-5
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\n" ); document.write( "Since the vertex is at (-5,7),
\n" ); document.write( "axis of symmetry: y = 7
\n" ); document.write( "Focus and Directrix ????
\n" ); document.write( "4p = 1/16
\n" ); document.write( "p = 1/64
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\n" ); document.write( "Focus: (-5+(1/64),7)
\n" ); document.write( "Directix: x = -5-(1/64)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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