document.write( "Question 691455: how do I find the Focus, Equation of the Directrix, and the equation of the axis of symmetry from the equation
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document.write( "x=(1/16)(y-7)^2-5 \n" );
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Algebra.Com's Answer #426705 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! how do I find the Focus, Equation of the Directrix, and the equation of the axis of symmetry from the equation \n" ); document.write( "x=(1/16)(y-7)^2-5 \n" ); document.write( "------ \n" ); document.write( "Since the vertex is at (-5,7), \n" ); document.write( "axis of symmetry: y = 7 \n" ); document.write( "Focus and Directrix ???? \n" ); document.write( "4p = 1/16 \n" ); document.write( "p = 1/64 \n" ); document.write( "---- \n" ); document.write( "Focus: (-5+(1/64),7) \n" ); document.write( "Directix: x = -5-(1/64) \n" ); document.write( "============================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================ \n" ); document.write( " |