document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=691448>Question 691448</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the domain for f(x)= <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28sqrt%285-x%29%2Bsqrt%28x-1%29%29%2F%28x-2%29sqrt%28x%29 ALIGN=MIDDLE  ALT=\"%28sqrt%285-x%29%2Bsqrt%28x-1%29%29%2F%28x-2%29sqrt%28x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Thanks for any help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #426703 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=426703\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the domain for f(x)= [sqrt(5-x)+sqrt(x-1)]/[(x-2)sqrt(x)]<BR>\n" );
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document.write( "sqrt(x) requires x >= 0<BR>\n" );
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document.write( "x-2 in the denominator requires x # 2<BR>\n" );
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document.write( "sqrt(5-x) requires x <= 5<BR>\n" );
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document.write( "sqrt(x-1) requires x >= 1<BR>\n" );
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document.write( "Putting that all together the domain is [1,2)U(2,5]<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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