document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=691406>Question 691406</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given that p = log(base c)(x), express log(base c)(square root x) + <BR>\n" );
document.write( "log(base c)(cx) in terms of p </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #426686 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=426686\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given that p = log(base c)(x), express <BR>\n" );
document.write( "log(base c)(square root x) + log(base c)(cx) in terms of p<BR>\n" );
document.write( "------<BR>\n" );
document.write( "= logc(x^(1/2)) + logc(c)+logc(x)<BR>\n" );
document.write( "------<BR>\n" );
document.write( "= (1/2)logc(x) + 1 + logc(x)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "= (3/2)logc(x) + 1<BR>\n" );
document.write( "---<BR>\n" );
document.write( "= p + 1<BR>\n" );
document.write( "=================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "================= <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );