document.write( "Question 691417: log(x+3)-log(x-3)=log(x-1) how do I solve? \n" ); document.write( "

Algebra.Com's Answer #426685 by mouk(232) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+log%28x%2B3%29-log%28x-3%29=log%28x-1%29+\"$
\n" ); document.write( " $\"+log%28%28x%2B3%29%2F%28x-3%29%29=log%28x-1%29+\"$ (using $\"+log%28a%29-log%28b%29+=+log%28a%2Fb%29+\"$ )
\n" ); document.write( " $\"+%28x%2B3%29%2F%28x-3%29=x-1+\"$ (taking anti-logarithms)
\n" ); document.write( " $\"+x%2B3+=+%28x-3%29%28x-1%29+\"$
\n" ); document.write( " $\"+x%2B3+=+x%5E2-4x%2B3+\"$
\n" ); document.write( " $\"+x%5E2-4x%2B3+=+x%2B3+\"$
\n" ); document.write( " $\"+x%5E2-5x=0+\"$
\n" ); document.write( " $\"+x%28x-5%29=0+\"$
\n" ); document.write( "so $\"+x=0+\"$ or $\"+x=5+\"$ \r
\n" ); document.write( "\n" ); document.write( "But original question had $\"+log%28x-3%29+\"$ so $\"+x-3+%3E0+\"$ or $\"+x%3E3+\"$ \r
\n" ); document.write( "\n" ); document.write( "so, solution is $\"+x=5+\"$
\n" ); document.write( " \n" ); document.write( "

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