document.write( "Question 691345: The length of a rectangle is 20 meters longer than the width. The perimeter must be between 80 and 100 meters. What are the possible values for the width of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #426682 by mouk(232)\"\" \"About 
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let \"+x+\" = width of rectangle, then length = \"+x+%2B+20+\"
\n" ); document.write( "so, perimeter = \"+x+%2B+x+%2B+%28x%2B20%29+%2B+%28x%2B20%29+\" = \"+4x+%2B+40+\"\r
\n" ); document.write( "\n" ); document.write( "but, The perimeter must be between 80 and 100 meters
\n" ); document.write( "so \"+80+%3C=+4x+%2B+40+%3C=+100+\"\r
\n" ); document.write( "\n" ); document.write( "consider, \"+80+%3C=+4x+%2B+40+\" then \"+4x+%2B+40+%3E=+80\"
\n" ); document.write( "so \"+4x+%3E=+40\"
\n" ); document.write( "so \"+x+%3E=+10\"\r
\n" ); document.write( "\n" ); document.write( "Now consider \"+4x+%2B+40+%3C=+100+\"
\n" ); document.write( "so \"+4x+%3C=+60+\"
\n" ); document.write( "so \"+x+%3C=+15+\"\r
\n" ); document.write( "\n" ); document.write( "Hence solution is \"+10+%3C=+x+%3C=+15+\"
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