document.write( "Question 691413: The sum of the digits of a two digit number is 10. The number formed by reversing the number is 4 less than 5 times the number. Find the original number?\r
\n" ); document.write( "\n" ); document.write( "Can you please help me out with this question I really don't understand? thanks in advance
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Algebra.Com's Answer #426681 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The sum of the digits of a two digit number is 10. The number formed by reversing the number is 4 less than 5 times the number. Find the original number?
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\n" ); document.write( "Let the number be 10t+u ; t is the 10's digit; u is units digit
\n" ); document.write( "The reverse number is 10u + 5
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\n" ); document.write( "Equations:
\n" ); document.write( "t + u = 10
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\n" ); document.write( "10u+t = 5(10t+u)-4
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\n" ); document.write( "Simplify the bottom equation:
\n" ); document.write( "10u+t = 50t+5u-4
\n" ); document.write( "49t - 5u = 4
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\n" ); document.write( "Substitute for t = 10-u for \"t\" and solve for \"u\":
\n" ); document.write( "49(10-u) - 5u = 4
\n" ); document.write( "490 - 54u = 4
\n" ); document.write( "54u = 486
\n" ); document.write( "u = 9
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\n" ); document.write( "Now, solve for \"t\" using t + u = 10
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\n" ); document.write( "t+9 = 10
\n" ); document.write( "t = 1
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\n" ); document.write( "The number is 10t+u = 10*1 + 9 = 19
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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