document.write( "Question 691413: The sum of the digits of a two digit number is 10. The number formed by reversing the number is 4 less than 5 times the number. Find the original number?\r
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document.write( "Can you please help me out with this question I really don't understand? thanks in advance \n" );
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Algebra.Com's Answer #426681 by stanbon(75887) ![]() You can put this solution on YOUR website! The sum of the digits of a two digit number is 10. The number formed by reversing the number is 4 less than 5 times the number. Find the original number? \n" ); document.write( "--- \n" ); document.write( "Let the number be 10t+u ; t is the 10's digit; u is units digit \n" ); document.write( "The reverse number is 10u + 5 \n" ); document.write( "-------- \n" ); document.write( "Equations: \n" ); document.write( "t + u = 10 \n" ); document.write( "------- \n" ); document.write( "10u+t = 5(10t+u)-4 \n" ); document.write( "=========== \n" ); document.write( "Simplify the bottom equation: \n" ); document.write( "10u+t = 50t+5u-4 \n" ); document.write( "49t - 5u = 4 \n" ); document.write( "==== \n" ); document.write( "Substitute for t = 10-u for \"t\" and solve for \"u\": \n" ); document.write( "49(10-u) - 5u = 4 \n" ); document.write( "490 - 54u = 4 \n" ); document.write( "54u = 486 \n" ); document.write( "u = 9 \n" ); document.write( "---- \n" ); document.write( "Now, solve for \"t\" using t + u = 10 \n" ); document.write( "--- \n" ); document.write( "t+9 = 10 \n" ); document.write( "t = 1 \n" ); document.write( "----- \n" ); document.write( "The number is 10t+u = 10*1 + 9 = 19 \n" ); document.write( "------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================ \n" ); document.write( " |