document.write( "Question 691308:
\n" ); document.write( "Bob and Steve want a 14% alcohol solution. how many ounces of a 12% alcohol solution must be mixed with a 20% alcohol solution to form 100 ounces of the 14% alcohol solution?
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Algebra.Com's Answer #426656 by checkley79(3341)\"\" \"About 
You can put this solution on YOUR website!
.12X+.20(100-X)=.14*100
\n" ); document.write( ".12X+20-.20X=14
\n" ); document.write( "-.08X=14-20
\n" ); document.write( "-.08X=-6
\n" ); document.write( "X=-6/-.08
\n" ); document.write( "X=75 OZ. USED OF THE 12% SOLUTION.
\n" ); document.write( "100-75=25 OZ. OF THE 20% SOLUTION IS USED.
\n" ); document.write( "PROOF:
\n" ); document.write( ".12*75+.20*25=.14*100
\n" ); document.write( "9+5=14
\n" ); document.write( "14=14
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