document.write( "Question 691308:
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document.write( "Bob and Steve want a 14% alcohol solution. how many ounces of a 12% alcohol solution must be mixed with a 20% alcohol solution to form 100 ounces of the 14% alcohol solution? \n" );
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Algebra.Com's Answer #426656 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! .12X+.20(100-X)=.14*100 \n" ); document.write( ".12X+20-.20X=14 \n" ); document.write( "-.08X=14-20 \n" ); document.write( "-.08X=-6 \n" ); document.write( "X=-6/-.08 \n" ); document.write( "X=75 OZ. USED OF THE 12% SOLUTION. \n" ); document.write( "100-75=25 OZ. OF THE 20% SOLUTION IS USED. \n" ); document.write( "PROOF: \n" ); document.write( ".12*75+.20*25=.14*100 \n" ); document.write( "9+5=14 \n" ); document.write( "14=14 \n" ); document.write( " |