document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=691349>Question 691349</A>: <I><SPAN STYLE=\"word-break: break-all;\"> TWICE a number added to half of itself equals 20.find the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #426639 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=426639\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> TWICE a number added to half of itself equals 20.find the number<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Let the number be \"x\":<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "2x + (1/2)x = 20<BR>\n" );
document.write( "----<BR>\n" );
document.write( "4x + x = 40<BR>\n" );
document.write( "3x = 40<BR>\n" );
document.write( "x = 13 1/3<BR>\n" );
document.write( "============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );