document.write( "Question 691275: Solve the equation and put the solution in exact form. \r
\n" ); document.write( "\n" ); document.write( "log(base 9)(x-4)+ log(base 9)(x-4)=1\r
\n" ); document.write( "\n" ); document.write( "This is what I have done.....
\n" ); document.write( "log(base 9) (x-4)(x-4)=1
\n" ); document.write( "(x-4)(x-4)=9
\n" ); document.write( "x^2- 4x -4x+16
\n" ); document.write( "x^2-8x+16=9
\n" ); document.write( "x^2-8x+7=0
\n" ); document.write( "(x-7)(x-1)
\n" ); document.write( "X=7, X=1\r
\n" ); document.write( "\n" ); document.write( "Answer (7,1)??? how would I put in exact form???? Is this even correct? Thanks!
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Algebra.Com's Answer #426622 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Your answers look right. Now you have to plug them
\n" ); document.write( "back into the original equation to verify them
\n" ); document.write( "\"+x+=+7+\"
\n" ); document.write( "I'll rewrite it slightly
\n" ); document.write( "\"+2%2Alog%28+9%2C+x-4+%29+=+1+\"
\n" ); document.write( "\"+2%2Alog%28+9%2C+7-4+%29+=+1+\"
\n" ); document.write( "\"+2%2Alog%28+9%2C+3+%29+=+1+\"
\n" ); document.write( "Note that \"+log%28+9%2C3+%29+=+1%2F2+\"
\n" ); document.write( "\"+2%2A%281%2F2%29+=+1+\"
\n" ); document.write( "OK
\n" ); document.write( "------
\n" ); document.write( "\"+x+=+1+\"
\n" ); document.write( "Here you run into trouble. You get
\n" ); document.write( "\"+2%2Alog%28+9%2C+x-4+%29+=+1+\"
\n" ); document.write( "\"+2%2Alog%28+9%2C+1-4+%29+=+1+\"
\n" ); document.write( "\"+2%2Alog%28+9%2C+-3+%29+=+1+\"
\n" ); document.write( "It asks you for the log to the base 9 which
\n" ); document.write( "gives you a negative number. There is no real
\n" ); document.write( "number that can do this, so
\n" ); document.write( "\"+x+=+7+\" is the only answer
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