document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=690928>Question 690928</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If sin theta = 5/6, and theta is in quadrant 2, find the exact value of:<BR>\n" );
document.write( "a) cos theta and b) sin(theta + pi/6) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #426618 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=426618\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If sin (t) = 5/6, and theta is in quadrant 2, <BR>\n" );
document.write( "find the exact value of:<BR>\n" );
document.write( "a) cos(t)<BR>\n" );
document.write( "Since sin(t) = y/r, y = 5 and r = 6<BR>\n" );
document.write( "Then x = sqrt[r^2-y^2] = sqrt(11) <BR>\n" );
document.write( "------<BR>\n" );
document.write( "Note: Remember; cos is negative in the QII<BR>\n" );
document.write( "------------<BR>\n" );
document.write( "So cos(t)= x/r = -sqrt(11)/6<BR>\n" );
document.write( "=====================\r<BR>\n" );
document.write( "\n" );
document.write( "b) sin(t + pi/6) = sin(t)*cos(pi/6) + cos(t)*sin(pi/6)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "= (5/6)(sqrt(3)/2) + (-sqrt(11)/6)(1/2)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "= (5sqrt(3) - sqrt(11))/12<BR>\n" );
document.write( "================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );