document.write( "Question 691248: A surveyor measures the angle of elevation of eye level to the top of a building 60 metres. If he is standing 40 metres away from the building and is 1.6 metres tall. How tall is the building? \r
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\n" ); document.write( "\n" ); document.write( "can you please help me out i dont really get this question? thanks in advance
\n" ); document.write( "for the first question it is the distance from his eye to the top of the building is 60 meters
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Algebra.Com's Answer #426616 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A surveyor measures the angle of elevation of eye level to the top of a building 60 metres. If he is standing 40 metres away from the building and is 1.6 metres tall. How tall is the building? \r
\n" ); document.write( "\n" ); document.write( "can you please help me out i dont really get this question? thanks in advance
\n" ); document.write( "for the first question it is the distance from his eye to the top of the building is 60 meters
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\n" ); document.write( "Draw the picture:
\n" ); document.write( "You have a right triangle
\n" ); document.write( "hypotenuse = 60 meters
\n" ); document.write( "base = 40 meters
\n" ); document.write( "height = sqrt(60^2-40^2) = sqrt(3200) = 40sqrt(2) meters
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\n" ); document.write( "Total height of the building is 1.6 meters + 40sqrt(2) meters
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\n" ); document.write( "Approximate answer: 1.6+40sqrt(2) = 58.169 meters (height of the bldg)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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