document.write( "Question 691248: A surveyor measures the angle of elevation of eye level to the top of a building 60 metres. If he is standing 40 metres away from the building and is 1.6 metres tall. How tall is the building? \r
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document.write( "can you please help me out i dont really get this question? thanks in advance
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document.write( "for the first question it is the distance from his eye to the top of the building is 60 meters \n" );
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Algebra.Com's Answer #426616 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A surveyor measures the angle of elevation of eye level to the top of a building 60 metres. If he is standing 40 metres away from the building and is 1.6 metres tall. How tall is the building? \r \n" ); document.write( "\n" ); document.write( "can you please help me out i dont really get this question? thanks in advance \n" ); document.write( "for the first question it is the distance from his eye to the top of the building is 60 meters \n" ); document.write( "------ \n" ); document.write( "Draw the picture: \n" ); document.write( "You have a right triangle \n" ); document.write( "hypotenuse = 60 meters \n" ); document.write( "base = 40 meters \n" ); document.write( "height = sqrt(60^2-40^2) = sqrt(3200) = 40sqrt(2) meters \n" ); document.write( "---- \n" ); document.write( "Total height of the building is 1.6 meters + 40sqrt(2) meters \n" ); document.write( "----- \n" ); document.write( "Approximate answer: 1.6+40sqrt(2) = 58.169 meters (height of the bldg) \n" ); document.write( "================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================= \n" ); document.write( " |