document.write( "Question 691259: Solve. \r
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Algebra.Com's Answer #426600 by nerdybill(7384)\"\" \"About 
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(7/(2+e^-x))=3
\n" ); document.write( "7=3(2+e^-x)
\n" ); document.write( "7/3 = 2+e^-x
\n" ); document.write( "7/3 - 2 = e^-x
\n" ); document.write( "ln(7/3 - 2) = -x
\n" ); document.write( "-ln(7/3 - 2) = x
\n" ); document.write( "-ln(7/3 - 6/3) = x
\n" ); document.write( "-ln(1/3) = x
\n" ); document.write( "1.099 = x
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