document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=691222>Question 691222</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how to solve this logarithmic equation:<BR>\n" );
document.write( "8logx=2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #426584 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=426584\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8log(x)=2 divide both sides by 8 --->log(x) = 1/4 = .25.  <P>\r<BR>\n" );
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document.write( "Remember the log identity log(basea)(x) = y if and only if a^y = x.<P>\r<BR>\n" );
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document.write( "log(x) = .25 is log base 10 (x) = .25 ---> 10^.25 = x.  10^.25 is approximately 1.778 so x = 1.778.<BR>\n" );
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