document.write( "Question 690988: Melissa invested a sum of money at 3% annual simple interest. She invested three times that sum at 5% annual simple interest. If her total yearly interest from both investments was $3600, how much was invested at 3%? \n" ); document.write( "
Algebra.Com's Answer #426463 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Part I 3.00% per annum---------------x \n" ); document.write( "Part II 5.00% per annum---------------3x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3.00% x + 5.00% * 3 x = 3600 \n" ); document.write( "0.03 x + 0.050 * 3 x = 3600 \n" ); document.write( "0.03 x + 0.15 x = 3600 \n" ); document.write( "0.18 x = 3600 \n" ); document.write( "/ 0.18 \n" ); document.write( "x= 20000 --- Fund A \n" ); document.write( "3x = 60000 Fund B \n" ); document.write( " \n" ); document.write( " CHECK \n" ); document.write( "20000 @ 3.00% = 600 \n" ); document.write( "60000 @ 5.00% = 3000 \n" ); document.write( "Interest= 3600 \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |