document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=690548>Question 690548</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve log 2x + log 12 = 3. Round to the nearest hundredth if necessary.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #426419 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=426419\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve log 2x + log 12 = 3. Round to the nearest hundredth if necessary.<BR>\n" );
document.write( "log 2x + log 12 = 3<BR>\n" );
document.write( "log(2x*12)=log(10^3)<BR>\n" );
document.write( "2x*12=10^3=1000<BR>\n" );
document.write( "2x=1000/12<BR>\n" );
document.write( "x=1000/24<BR>\n" );
document.write( "x&#8776;41.67 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );