document.write( "Question 690729: You run at a rate of 4 miles per hour and your friend runs at a rate of 3.5 miles per hour. Your friend starts running 10 minutes before you, and you run for a half hour on the same path. Will you catch up to your friend? Use a graph to support your answer. \n" ); document.write( "
Algebra.Com's Answer #426406 by ankor@dixie-net.com(22740)\"\" \"About 
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You run at a rate of 4 miles per hour and your friend runs at a rate of 3.5 miles per hour.
\n" ); document.write( " Your friend starts running 10 minutes before you, and you run for a half hour on the same path.
\n" ); document.write( " Will you catch up to your friend? Use a graph to support your answer.
\n" ); document.write( ":
\n" ); document.write( "The question is, Does your friend run further in 40 min than you run in 30 min.
\n" ); document.write( ":
\n" ); document.write( "Friend: \"40%2F60\" * 3.5 = 2\"1%2F3\" mi
\n" ); document.write( "You: \"30%2F60\" * 4 = 2 mi
\n" ); document.write( "You won't catch up in a half hour
\n" ); document.write( ":
\n" ); document.write( "Graph it in ft/min; You in red, friend in green
\n" ); document.write( ":
\n" ); document.write( "4 mph: \"%284%2A5280%29%2F60\" = 352 ft/min; y = 352x
\n" ); document.write( "3.5 mph: \"%283.5%2A5280%29%2F60\" = 308 ft/min; y = 308(x+10)
\n" ); document.write( ":
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-10%2C+100%2C+-5000%2C+30000%2C+353x%2C+308%28x%2B10%29%29+\"
\n" ); document.write( "You can see that at 30 min green is still ahead of red
\n" ); document.write( "Take about 70 min for you to catch your friend
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