document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=690644>Question 690644</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log4(3x-3) = log4(x+1) + 2log4(4) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #426369 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=426369\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log4(3x-3) = log4(x+1) + 2log4(4)<BR>\n" );
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document.write( "log4(3x-3) = log4[(x+1)*4^2]<BR>\n" );
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document.write( "Equate the inverse logs to solve for \"x\":<BR>\n" );
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document.write( "3x-3 = 16(x+1)<BR>\n" );
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document.write( "3x-3 = 16x + 16<BR>\n" );
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document.write( "13x = -19<BR>\n" );
document.write( "x = -19/13<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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