document.write( "Question 690520: The width of a rectangle is 4 inches less than one half the length. Find the length and width of the rectangle if the perimeter is 46 inches. \n" ); document.write( "

Algebra.Com's Answer #426338 by Stitch(470) $\"\"$ $\"About$

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Set-Up
\n" ); document.write( "--------------
\n" ); document.write( "X = length
\n" ); document.write( "Y = width
\n" ); document.write( "Equation 1: $\"46+=+2X+%2B+2Y\"$
\n" ); document.write( "Equation 2: $\"X+=+2Y+%2B+8\"$ That came from 2*(Y+4)\r
\n" ); document.write( "\n" ); document.write( "Solution:
\n" ); document.write( "--------------
\n" ); document.write( "Plug (2Y + 8) into equation 1 for X
\n" ); document.write( "Equation 1: $\"46+=+2X+%2B+2Y\"$
\n" ); document.write( " $\"46+=+2%282Y+%2B+8%29+%2B+2Y\"$ Simplify
\n" ); document.write( " $\"46+=+4Y+%2B+16+%2B+2Y\"$ Combine like terms
\n" ); document.write( " $\"46+=+6Y+%2B+16\"$ Subtract 16 from both sides
\n" ); document.write( " $\"30+=+6y\"$ Divide both sides by 6
\n" ); document.write( " $\"highlight%285+=+Y%29\"$
\n" ); document.write( "Now plug 5 into equation 2 for Y
\n" ); document.write( "Equation 2: $\"X+=+2Y+%2B+8\"$
\n" ); document.write( " $\"X+=+2%2A%285%29+%2B+8\"$
\n" ); document.write( " $\"highlight%28X+=+18%29\"$ \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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