document.write( "Question 690523: factor
\n" ); document.write( "2x^6-10x^4+12x^2
\n" ); document.write( "i think it get factored down to 2x^2(x^4-5x^2+6x) but im not sure how to get it smaller
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Algebra.Com's Answer #426329 by Stitch(470)\"\" \"About 
You can put this solution on YOUR website!
Given: \"2X%5E6+-+10X%5E4+%2B+12X%5E2\"
\n" ); document.write( "You were right about pulling a 2X^2 out from each term but you left an X on your 6. It shold be:
\n" ); document.write( "\"2X%5E2%2A%28X%5E4+-+5X%5E2+%2B+6%29\"
\n" ); document.write( "Now find the factors of 6
\n" ); document.write( "6: 1, 2, 3, 6
\n" ); document.write( "Since 6 is positve, the two factors have to be both positive or both negative.
\n" ); document.write( "However, note that the 5X^2 is negative. That means you need at least one negative factor.
\n" ); document.write( "So if you have -1 + -6 = -7.
\n" ); document.write( "If you use -2 + -3 = -5. That fits your equation\r
\n" ); document.write( "\n" ); document.write( "So now the equation is:\"2X%5E2%2A%28%28X%5E2-3%29%2A%28X%5E2-2%29%29\"
\n" ); document.write( "or just simply \"2X%5E2+%2A+%28X%5E2-3%29+%2A+%28X%5E2-2%29\"
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