document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=690405>Question 690405</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The difference of two positive numbers is 13.  The larger is twice the smaller decreased by 3.  Find the two numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #426299 by </B><A HREF=/tutors/aboutme.mpl?userid=farah><B>farah(18)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=farah><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=farah><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=426299\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let y be the larger number n x be smaller number.. ok, y-x=13,y=2(x-3)..so,u will get 2x-6-x=13,hence x=19..if x is 19,then y=19+13,y=32..please check wether the different of both number is 13 or not..let me do it for u,y is 32 and x is19,so 32-19=13,thats mean the numbers are 32 and 19.sorry if i'm doing wrong. </SPAN>\n" );
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