document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=690429>Question 690429</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 15 less than twice the first number. Their difference is 5 less than twice the second number. Find each of the numbers.\r<BR>\n" );
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document.write( "I need to find the answer using substitution. \r<BR>\n" );
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document.write( "so far, I got<BR>\n" );
document.write( "X represents the first number<BR>\n" );
document.write( "Y represents the second number\r<BR>\n" );
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document.write( "x+y=2x-15<BR>\n" );
document.write( "x-y=2y-5\r<BR>\n" );
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document.write( " How do i find the x?  Well I know the process... but the numbers confuses me... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #426296 by </B><A HREF=/tutors/aboutme.mpl?userid=farah><B>farah(18)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=farah><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=farah><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=426296\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i just continue ur work, based on second equation, x=2y-5+y, x=3y-5,so subtitude x=3y-5 into first equation. 3y-5+y=2(3y-5)-15,it will be y=-2..if y=-2,then x=3(-2)-5,hence x=-11...sorry if i'm doing wrong. </SPAN>\n" );
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