document.write( "Question 690398: if cos(a) is 2/3 and sin(b) is 4/5 what is cos(a+b) \n" ); document.write( "
Algebra.Com's Answer #426278 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! if cos(a) is 2/3 and sin(b) is 4/5 what is cos(a+b) \n" ); document.write( ".. \n" ); document.write( "cos a=2/3=adj side/hypotenuse \n" ); document.write( "opp side=√(3^2-2^2)=√(9-4)=√5 \n" ); document.write( "sin a=√5/3 \n" ); document.write( ".. \n" ); document.write( "sin b=4/5 (3-4-5 right triangle) \n" ); document.write( "cos b=3/5 \n" ); document.write( ".. \n" ); document.write( "cos(a+b)=cos a cos b -sin a sin b \n" ); document.write( "=2/3*3/5 -√5/3*4/5 \n" ); document.write( "=6/15-4√5/15 \n" ); document.write( "=(6-4√5)/15 \n" ); document.write( ".. \n" ); document.write( "calculator check: \n" ); document.write( "a=cos^1(2/3)≈.8411 \n" ); document.write( "b=sin^-1(4/5)=.9273 \n" ); document.write( "cos(a+b)=cos(1.7684)=-0.1962.. \n" ); document.write( "(6-4√5)/15=-0.1962.. \n" ); document.write( " |