document.write( "Question 61885: I need someone to show me how to graph this . write the equation of the line with slope-1/2 and -y intercept(0,3) then graph
\n" ); document.write( "I worked it out 2y=-x+6 y=3 slope -1/2 I am not sure if that is correct and I do not know how to graph it. \n" ); document.write( "

Algebra.Com's Answer #42626 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
write the equation of the line with slope-1/2 and -y intercept(0,3) then graph
\n" ); document.write( "---------
\n" ); document.write( "The slope-intercept form of the line is y=mx+b
\n" ); document.write( "You are told the slope is 1/2 and the y-intercept is 3
\n" ); document.write( "So, the equation is y=(1/2)x+3
\n" ); document.write( "To graph you could find the x-intercept:
\n" ); document.write( "Let y=0, then 0=(1/2)x+3
\n" ); document.write( "(1/2)x=-3
\n" ); document.write( "x=-6
\n" ); document.write( "You now have two points: (0,3) and (-6,0)
\n" ); document.write( "Plot those two points and draw a line thru
\n" ); document.write( "them. That is your graph.
\n" ); document.write( " $\"graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C%281%2F2%29x%2B3%29\"$
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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