document.write( "Question 689652: Patricia flew a small airplane for 3 hours with the wind and traveled 585km. The return trip against the wind took 5 hours. Find the rate at which she flew in still air. \r
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\n" ); document.write( "\n" ); document.write( "What I have tried and failed:\r
\n" ); document.write( "\n" ); document.write( "3(r+w)=585 --> 3r+3w=585
\n" ); document.write( "5(r-w)=585 --> 5r-5w=585\r
\n" ); document.write( "\n" ); document.write( "15r+15w=2925 15r=8775
\n" ); document.write( "15r-15w=1755 r=585 3(585)+3w=585
\n" ); document.write( " 1755+3w=585
\n" ); document.write( " -1755 -1755 <--- I figured this was wrong
\n" ); document.write( " because it was negative.. \r
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Algebra.Com's Answer #426209 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
a small airplane for 3 hours with the wind and traveled 585km.
\n" ); document.write( " The return trip against the wind took 5 hours.
\n" ); document.write( "Find the rate in still air
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\n" ); document.write( "Let's do it this way
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\n" ); document.write( "Write a distance equation for each way
\n" ); document.write( "3(r+w) = 585
\n" ); document.write( "5(r-w) = 585
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\n" ); document.write( "Simplify, divide the 1st equation by 3, divide the 2nd equation by 5, results:
\n" ); document.write( "r + w = 195
\n" ); document.write( "r - w = 117
\n" ); document.write( "-------------addition eliminates w, find r
\n" ); document.write( "2r = 312
\n" ); document.write( "r = 312/2
\n" ); document.write( "r = 156 km/h in still air
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\n" ); document.write( "You can confirm this, find w and check in the original equations
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