document.write( "Question 690131: Hello, I was wondering how you would solve the following;
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document.write( "Log2(x)+log2(x-3)=2
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document.write( "As well as that, I was wonder how to simplify the following;
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document.write( "Log5(8)-log5(40)-log5(50)+log5(10)
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document.write( "Thanks, Tom. \n" );
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Algebra.Com's Answer #426183 by DrBeeee(684)![]() ![]() ![]() You can put this solution on YOUR website! It takes me back about 64 years when I last used logs, but I'll try to remember. \n" ); document.write( "First use the formula, if \n" ); document.write( "(1) Logn(N) = x then \n" ); document.write( "(2) N = n^x \n" ); document.write( "I hope this is right, is it? \n" ); document.write( "Also, I know that \n" ); document.write( "(3) Logn(a) + Logn(b) = Logn(a*b). \n" ); document.write( "Using (3) on your problem yields \n" ); document.write( "(4) Log2(x*(x-3)) = 2 \n" ); document.write( "Now use (2) on (4) we get \n" ); document.write( "(5) x*(x-3) = 2^2 or \n" ); document.write( "(6) x^2 - 3x -4 = 0, which factors to \n" ); document.write( "(7) (x-4)(x+1) = 0, which gives the set of roots \n" ); document.write( "(8) x = {4,-1} \n" ); document.write( "Let's check these values using the given equation. \n" ); document.write( "Is (Log2(4) + Log2(4-3) = 2)? \n" ); document.write( "Is (2 + 0 = 2)? Yes \n" ); document.write( "Is (Log2(-1*(-1-3)) = 2)? \n" ); document.write( "Is (Log2(4) = 2)? \n" ); document.write( "Is (4 = 2^2)? \n" ); document.write( "Is (4 = 4)? Yes \n" ); document.write( "Answer: The solution pair is x = {4,-1} \n" ); document.write( "We can use (3) to simplify your second problem to \n" ); document.write( "(9) Log5(8/40/50*10) or \n" ); document.write( "(10) Log5(1/5/50*10) or \n" ); document.write( "(11) Log5(1/250*10) or \n" ); document.write( "(12) Log5(1/25) \n" ); document.write( "Let y = (12) and \n" ); document.write( "Using (1) and (2) on (12) we get \n" ); document.write( "(13) 1/25 = 5^y or \n" ); document.write( "(14) y = -2 \n" ); document.write( "Answer: Log5(8) - Log5(40) - Log5(50) + Log5(10) = -2. \n" ); document.write( " |