document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=690120>Question 690120</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "I am doing substitution method for equations. 2y+x=9, and x=3y-3. Do I start with putting the 2y-9 in 3y-3 because \"x\" has no base in 2y+x=9 except a 1 in x. Not sure on the next way to go. My textbook does not show this type of problem.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #426180 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=426180\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2y+X=9<BR>\n" );
document.write( "X=3Y-3<BR>\n" );
document.write( "2Y+(3Y-3)=9<BR>\n" );
document.write( "5Y-3=9<BR>\n" );
document.write( "5Y=9+3<BR>\n" );
document.write( "5Y=12 <BR>\n" );
document.write( "Y=12/5 ANS.<BR>\n" );
document.write( "X=3*12/5-3<BR>\n" );
document.write( "X=36/5-3<BR>\n" );
document.write( "X=36/5-15/5<BR>\n" );
document.write( "X=21/5 ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "2(12/5)+21/5=9<BR>\n" );
document.write( "24/5+21/5=9<BR>\n" );
document.write( "45/5=9<BR>\n" );
document.write( "9=9 </SPAN>\n" );
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