document.write( "Question 61801This question is from textbook
\n" ); document.write( ": Please help with the following problem: e^x = 2^x+1 \n" ); document.write( "
Algebra.Com's Answer #42616 by funmath(2933)\"\" \"About 
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e^x = 2^(x+1)
\n" ); document.write( "ln(e^x)=ln(2^(x+1))
\n" ); document.write( "xln(e)=(x+1)ln(2)
\n" ); document.write( "x(1)=(x+1)ln(2)
\n" ); document.write( "x=xln(2)+ln(2)
\n" ); document.write( "x-xln(2)=ln(2)
\n" ); document.write( "x(1-ln(2))=ln(2)
\n" ); document.write( "x(1-ln(2))/(1-ln(2))=ln(2)/(1-ln(2))
\n" ); document.write( "x=ln(2)/(1-ln(2))
\n" ); document.write( "x=2.258891353 approximatlely.
\n" ); document.write( "Happy Calculating!!!
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