document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=689772>Question 689772</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rancher wants to enclose a rectangular field with  220 ft of fencing. One side is a river and will not require a fence. What is the maximum area that can be enclosed?\r<BR>\n" );
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document.write( "Please and Thanks a lot! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #426154 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=426154\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A rancher wants to enclose a rectangular field with 220 ft of fencing.<BR>\n" );
document.write( " One side is a river and will not require a fence.<BR>\n" );
document.write( " What is the maximum area that can be enclosed?<BR>\n" );
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document.write( "The field requires only 3 sides of fence, therefore<BR>\n" );
document.write( "L + 2W = 220<BR>\n" );
document.write( "L = (220-2W); we can use this for substitution in the Area equation<BR>\n" );
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document.write( "Area<BR>\n" );
document.write( "A = L*W<BR>\n" );
document.write( "replace L with (220-2W)<BR>\n" );
document.write( "A = W(220-2W)<BR>\n" );
document.write( "A = -2W^2 + 220W<BR>\n" );
document.write( "A quadratic equation, max A occurs at the axis of symmetry, x = -b/(2a) <BR>\n" );
document.write( "In this equation<BR>\n" );
document.write( "W = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-220%29%2F%282%2A-2%29 ALIGN=MIDDLE  ALT=\"%28-220%29%2F%282%2A-2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "W = 55 ft is the width for max area<BR>\n" );
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document.write( "Find the max area<BR>\n" );
document.write( "A = -2(55^2) + 220(55)<BR>\n" );
document.write( "A = -2(3025) + 12100<BR>\n" );
document.write( "A = 6050 sq/ft is the max area<BR>\n" );
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document.write( "Confirm this with the dimensions calculated; 110 * 55 = 6050 </SPAN>\n" );
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