document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=690031>Question 690031</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am doing the substitution of equations method. y=5-4x,2x-3y=13. When I rewrite as 5-4x+2x-3y=13.Would I first have to subtract 5 from 4x before mulitiplying the x's. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #426130 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=426130\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=5-4x<BR>\n" );
document.write( "2x-3y=13<BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "Substitute for \"y\" and solve for \"x\":<BR>\n" );
document.write( "2x -3(5-4x) = 13<BR>\n" );
document.write( "2x - 15 + 12x = 13<BR>\n" );
document.write( "14x = 28<BR>\n" );
document.write( "x = 2<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "Solve for \"y\" using y = 5-4x<BR>\n" );
document.write( "y = 5 - 4*2<BR>\n" );
document.write( "y = -3<BR>\n" );
document.write( "============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============ </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );