document.write( "Question 690021: I have to solve this problem for school. Please help\r
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document.write( "Graph this rational function: \r
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document.write( "T(w)= w^2+2w+4/w-1
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Algebra.Com's Answer #426127 by jim_thompson5910(35256) ![]() You can put this solution on YOUR website! w-1 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "w = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the vertical asymptote is w = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plug in w = 0 to get (w^2+2w+4)/(w-1) = ((0)^2+2(0)+4)/(0-1) = -4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the y-intercept is (0,-4)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since the discriminant of w^2+2w+4 is negative, there are no real solutions, which means that there are no x-intercepts.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use polynomial long division to get the quotient w+3. So the oblique asymptote is y = x+3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So what we have is this\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note: The blue vertical line should be a dashed line since it's the vertical asymptote. The blue diagonal line should be a dashed line since it's the oblique asymptote. \n" ); document.write( " \n" ); document.write( " |