document.write( "Question 689679: Solve the exponential equation algebraically. Show steps\r
\n" ); document.write( "\n" ); document.write( "3^x=2^x-1
\n" ); document.write( "

Algebra.Com's Answer #426081 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
What you posted means
\n" ); document.write( "\"3%5Ex=2%5Ex-1\" (with the -1 not in the exponent)
\n" ); document.write( "but I suspect the equation is:
\n" ); document.write( "\"3%5Ex=2%5E%28x-1%29\" (with the -1 in the exponent)
\n" ); document.write( "These are very different equations with very different solutions.

\n" ); document.write( "Please re-post your question. If you really meant the first equation use
\n" ); document.write( "3^x=(2^x)-1
\n" ); document.write( "to make it clear. If the equation is supposed to be what I suspect then use:
\n" ); document.write( "3^x=2^(x-1)
\n" ); document.write( "
\n" );