document.write( "Question 689700: Hello, I was wondering how you would solve this equation.\r
\n" ); document.write( "\n" ); document.write( "log base 5(x+3)=1\r
\n" ); document.write( "\n" ); document.write( "Thank you! \n" ); document.write( "

Algebra.Com's Answer #426079 by jsmallt9(3758) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"log%285%2C+%28x%2B3%29%29+=+1\"$
\n" ); document.write( "Solving equations where the variable is in the argument of a logarithm usually starts with transforming the equation into one of the following forms:
\n" ); document.write( "log(expression) = number
\n" ); document.write( "or
\n" ); document.write( "log(expression) = log(expression)

\n" ); document.write( "Your equation is already in the first form. The next step with this form is to rewrite the equation in exponential form. In general $\"log%28a%2C+%28p%29%29+=+q\"$ is equivalent to $\"a%5Eq+=+p\"$ . Using this pattern on your equation:
\n" ); document.write( " $\"5%5E1+=+x%2B3\"$
\n" ); document.write( "The left side simplifies:
\n" ); document.write( " $\"5+=+x%2B3\"$
\n" ); document.write( "Subtracting 3:
\n" ); document.write( " $\"2+=+x\"$ \n" ); document.write( "

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