document.write( "Question 689687: Solve the logarithmic equation algebraically. Show steps\r
\n" ); document.write( "\n" ); document.write( "log x=-4\r
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Algebra.Com's Answer #426078 by jsmallt9(3758) $\"\"$ $\"About$

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Solving equations where the variable is in the argument of a logarithm usually starts with transforming the equation into one of the following forms:
\n" ); document.write( "log(expression) = number
\n" ); document.write( "or
\n" ); document.write( "log(expression) = log(expression)

\n" ); document.write( "Your equation is already in the first form. The next step with this form is to rewrite the equation in exponential form. In general $\"log%28a%2C+%28p%29%29+=+q\"$ is equivalent to $\"a%5Eq+=+p\"$ . Using this patter on your equation (and the fact the the base of log is 10):
\n" ); document.write( " $\"10%5E%28-4%29+=+x\"$
\n" ); document.write( "The left side simplifies to:
\n" ); document.write( " $\"1%2F10000+=+x\"$ \n" ); document.write( "

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