document.write( "Question 689727: start at 12 o'clock: what will minute hand catch the hour hand (this was a problem given to me 60 yrs ago--am I right in remembering the answer to be 16 4/11?). THANKS \n" ); document.write( "
Algebra.Com's Answer #426046 by ankor@dixie-net.com(22740)\"\" \"About 
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start at 12 o'clock: when will the minute hand catch the hour hand? (this was a problem given to me 60 yrs ago--am I right in remembering the answer to be 16 4/11?)
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\n" ); document.write( "I don't think so, won't the minute hand catch up with the hour hand after one hr?
\n" ); document.write( "The hour hand will be slightly passed 1 when the minute hand catches it.
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\n" ); document.write( "Using degrees, one hr = 30 degrees, 1 min = 6 degrees
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\n" ); document.write( "let m = minutes after the hr when this happens
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\n" ); document.write( "Hour hand degrees = min hand degrees
\n" ); document.write( "30 + \"m%2F60\"*30 = 6m
\n" ); document.write( "30 + \"m%2F2\" = 6m
\n" ); document.write( "mult by 2
\n" ); document.write( "60 + m = 12m
\n" ); document.write( "60 = 12m - m
\n" ); document.write( "60 = 11m
\n" ); document.write( "m = 60/11
\n" ); document.write( "m = 5\"5%2F11\" minutes when it catches the hour hand
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