document.write( "Question 689761: How much pure acid must be added to 25 gallons of 25% solution to obtain a 50% solution?\r
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document.write( "What I tried: \r
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document.write( "25(100x + 25) = 50(100x)
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document.write( "2500x + 625 = 5000x
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document.write( "625 = 2500x
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document.write( "x = 1/4 (.25)\r
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document.write( "But something doesn't seem quite right! Thank you in advance! \n" );
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Algebra.Com's Answer #426042 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Stop guessing.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve for \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "Egw to Beta kai to Sigma \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |