document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=689597>Question 689597</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me figure out how to find the x intercepts of this equation:\r<BR>\n" );
document.write( "\n" );
document.write( "y= -3x^3 + 18x - 27x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #426009 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=426009\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I think the problem is:<BR>\n" );
document.write( "y= -3x^3 + 18x^2 - 27x<BR>\n" );
document.write( "x intercept occur when y = 0<BR>\n" );
document.write( "-3x^3 + 18x^2 - 27x = 0<BR>\n" );
document.write( "Factor out -3x<BR>\n" );
document.write( "-3x(x^2 - 6x + 9) = 0<BR>\n" );
document.write( "a perfect square is revealed, factor it to<BR>\n" );
document.write( "-3x(x-3)(x-3) = 0<BR>\n" );
document.write( "the x intercepts:<BR>\n" );
document.write( "-3x = 0<BR>\n" );
document.write( "x = 0<BR>\n" );
document.write( "and<BR>\n" );
document.write( "x = 3  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );