document.write( "Question 689580: How do you solve (7/9)v + 5/12 - (3/18)v ≥ (3/4)v + 1/3? Please show the step-by-step solution because this is a homework problem. I tried the problem, but I know I am wrong. I just can't find the mistake!
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Algebra.Com's Answer #426004 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
How do you solve (7/9)v + 5/12 - (3/18)v ≥ (3/4)v + 1/3?
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\n" ); document.write( "\"%287%2F9%29\"v + \"5%2F12\" - \"%283%2F18%29\"v >= \"%283%2F4%29\"v + \"1%2F3\"
\n" ); document.write( "We can get rid of all these denominators by multiplying by 36, resulting in
\n" ); document.write( "4(7v) + 3(5) - 2(3v) >= 9(3v) + 12
\n" ); document.write( "do the math
\n" ); document.write( "28v + 15 - 6v >= 27v + 12
\n" ); document.write( "Combine like terms
\n" ); document.write( "28v - 6v - 27v >= 12 - 15
\n" ); document.write( "-5v >= -3
\n" ); document.write( "v has to be positive, mult by -1, this reverses the inequality sign:
\n" ); document.write( "5v <= 3
\n" ); document.write( "v <= \"3%2F5\"
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