document.write( "Question 689520: A company offers a starting salary of $38,000 with raises of $2,000 per year. Find the total salary over a ten-year period. \n" ); document.write( "

Algebra.Com's Answer #425988 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+s+=+38000+\"$
\n" ); document.write( "Let $\"+r+=+2000+\"$
\n" ); document.write( "Let $\"+S+\"$ = total salary
\n" ); document.write( "---------------------
\n" ); document.write( "The first year is $\"+S+=+s+%2B+r%2A0+\"$
\n" ); document.write( "The second year is $\"+S+=+s+%2B+r%2A1+\"$
\n" ); document.write( "The third year is $\"+S+=+s+%2B++r%2A2+\"$
\n" ); document.write( "Adding up the salary for years 1 through 10
\n" ); document.write( " $\"+S+=+10s+%2B+r%2A%28+0+%2B+1+%2B+2+%2B+3+%2B+4+%2B+5+%2B+6+%2B+7+%2B+8+%2B+9+%29+\"$
\n" ); document.write( "(1) $\"+S+=+10s+%2B+r%2A%281%2F2%29%2A%289%2A10%29+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+S+=+10%2A38000+%2B+2000%2A%281%2F2%29%2A%289%2A10%29+\"$
\n" ); document.write( " $\"+S+=+380000+%2B+90000+\"$
\n" ); document.write( " $\"+S+=+470000+\"$
\n" ); document.write( "The total salary over a ten year period is $470,000
\n" ); document.write( "---------------------------------
\n" ); document.write( "Formula (1) seems to work
\n" ); document.write( "The total salary over a thousand year period would be:
\n" ); document.write( "(1) $\"+S+=+1000s+%2B+r%2A%281%2F2%29%2A%28+999%2A1000+%29+\"$
\n" ); document.write( " \r
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