document.write( "Question 689451: A swimming pool is 100 feet long and 50 feet wide. It is 7 feet deep at the deep end and has a beach entry(0feet deep) at the shallow end. The bottom of the pool has a constant slope. What is the surface area of the inside of the pool? If it helps the water capacity is 17500ft^3 or 130 000 US gallons. The answer in the answer key is 6062ft^2 but I have no idea how they got there. \n" ); document.write( "
Algebra.Com's Answer #425962 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A swimming pool is 100 feet long and 50 feet wide. It is 7 feet deep at the deep end and has a beach entry(0feet deep) at the shallow end. The bottom of the pool has a constant slope. What is the surface area of the inside of the pool? \n" ); document.write( "--------------- \n" ); document.write( "A cross-section of the water in the pool from the \"beach\" \n" ); document.write( "to the deepest point is a right triangle with height = 7 ft, \n" ); document.write( "and base = 100 ft. \n" ); document.write( "------ \n" ); document.write( "The area of that rectangle is (1/2)7*100 = 350 sq. ft. \n" ); document.write( "2 sides of the pool are each 350 sq. ft. \n" ); document.write( "---- \n" ); document.write( "The wall at the deepest point has area = 7*50 = 350 sq. ft \n" ); document.write( "--- \n" ); document.write( "The length of the bottom of the pool is sqrt[100^2 + 7^2] = 100.25 sq. ft \n" ); document.write( "The area of the bottom of the pool is 100.25*50 = 5012 sq. ft \n" ); document.write( "---------- \n" ); document.write( "Adding the 3 walls and the bottom surface you get 3(350) + 5012 = 6062.24 \n" ); document.write( "sq ft. \n" ); document.write( "=============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |