document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=689441>Question 689441</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Using the intermediate value theorem, show that the polynomial has a real zero between 1 and 2.\r<BR>\n" );
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document.write( "f(x)=x^3-x-1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #425957 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=425957\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x) = x^3-x-1\r<BR>\n" );
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document.write( "f(1) = (1)^3-1-1\r<BR>\n" );
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document.write( "f(1) = 1-1-1\r<BR>\n" );
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document.write( "f(1) = -1\r<BR>\n" );
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document.write( "f(x) = x^3-x-1\r<BR>\n" );
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document.write( "f(2) = (2)^3-2-1\r<BR>\n" );
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document.write( "f(2) = 8-2-1\r<BR>\n" );
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document.write( "f(2) = 5\r<BR>\n" );
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document.write( "Since f(1) = -1 and f(2) = 5, we have a change from a negative number to a positive number, so there's a zero between x = 1 and x = 2 </SPAN>\n" );
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