document.write( "Question 689225: Person A can paint the neighbor's house 5 times as fast as Person B. The year A and B worked together, it took them 7 days. How long would it take each to paint the house? \n" ); document.write( "
Algebra.Com's Answer #425899 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Person A can paint the neighbor's house 5 times as fast as Person B. \n" ); document.write( " The year A and B worked together, it took them 7 days. \n" ); document.write( " How long would it take each to paint the house? \n" ); document.write( ": \n" ); document.write( "Let t = time required by A to paint the house \n" ); document.write( "\" Person A can paint the neighbor's house 5 times as fast as Person B.\" \n" ); document.write( "therefore: \n" ); document.write( "5t = time required by B \n" ); document.write( ": \n" ); document.write( "Let the completed job = 1 (a painted house) \n" ); document.write( ": \n" ); document.write( "Each will do a fraction of the job, the two fractions add up to 1 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "multiply by 5t to get rid of the denominators, resulting in: \n" ); document.write( "5(7) + 7 = 5t \n" ); document.write( "35 + 7 = 5t \n" ); document.write( "42 = 5t \n" ); document.write( "t = 42/5 \n" ); document.write( "t = 8.4 days required by A \n" ); document.write( "then \n" ); document.write( "5(8.4) = 42 days required by B \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this using a calc \n" ); document.write( " \n" ); document.write( ".83 + .17 = 1\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |