document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=689220>Question 689220</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sq rt of 50x^7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #425874 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=425874\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Is the task to simplify?  You can factor the number and the x terms to find perfect squares, then pull them out of the root.  For x raised to some power factor out an even power then the square root of that will be x to 1/2 the original power.  For example x^3 = x*x^2 and the square root of x^2 is x.<P><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2850x%5E7%29+-+sqrt%282%2A25%2Ax%5E6%2Ax%29+=+5x%5E3sqrt%282x%29 ALIGN=MIDDLE  ALT=\"sqrt%2850x%5E7%29+-+sqrt%282%2A25%2Ax%5E6%2Ax%29+=+5x%5E3sqrt%282x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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