document.write( "Question 689065: what are three consecutive numbers such that twice the sum of the first two numbers is 24 more than 3 times the third number. \n" ); document.write( "
Algebra.Com's Answer #425837 by ReadingBoosters(3246)\"\" \"About 
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x, x+1, x+2
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\n" ); document.write( "2(x+x+1) = 24 + 3(x+2)
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\n" ); document.write( "2(2x+1) = 24 + 3x+6
\n" ); document.write( "4x + 2 = 24 + 3x + 6
\n" ); document.write( "4x - 3x = 24 + 6 - 2
\n" ); document.write( "x = 28
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\n" ); document.write( "Numbers are \"highlight_green%2828%29\", \"highlight_green%2829%29\", and \"highlight_green%2830%29\"
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\n" ); document.write( "Check
\n" ); document.write( "2(28+29) = 2(57) = 114
\n" ); document.write( "3(30) + 24 = 90 + 24 = 114
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