document.write( "Question 689065: what are three consecutive numbers such that twice the sum of the first two numbers is 24 more than 3 times the third number. \n" ); document.write( "
Algebra.Com's Answer #425837 by ReadingBoosters(3246)![]() ![]() ![]() You can put this solution on YOUR website! x, x+1, x+2 \n" ); document.write( "... \n" ); document.write( "2(x+x+1) = 24 + 3(x+2) \n" ); document.write( "... \n" ); document.write( "2(2x+1) = 24 + 3x+6 \n" ); document.write( "4x + 2 = 24 + 3x + 6 \n" ); document.write( "4x - 3x = 24 + 6 - 2 \n" ); document.write( "x = 28 \n" ); document.write( "... \n" ); document.write( "Numbers are \n" ); document.write( "... \n" ); document.write( "Check \n" ); document.write( "2(28+29) = 2(57) = 114 \n" ); document.write( "3(30) + 24 = 90 + 24 = 114 \n" ); document.write( "…………………………… \n" ); document.write( "Have more questions? Get them all answered at once. \n" ); document.write( "HomeworkHelpers@ReadingBoosters.com \n" ); document.write( "Personalized coaching: www.MyHomeworkAnswers.com \n" ); document.write( "--Reading Boosters \n" ); document.write( " \n" ); document.write( " |