document.write( "Question 688793: In(x-1)+In6= In(3x) \n" ); document.write( "
Algebra.Com's Answer #425827 by ankor@dixie-net.com(22740)\"\" \"About 
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In(x-1)+ In(6) = In(3x)
\n" ); document.write( "adding logs mean multiply so we can write this as
\n" ); document.write( "ln[6(x-1)] = ln(3x)
\n" ); document.write( "therefore
\n" ); document.write( "6(x-1) = 3x
\n" ); document.write( "6x - 6 = 3x
\n" ); document.write( "6x - 3x = +6
\n" ); document.write( "3x = 6
\n" ); document.write( "x = 2
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\n" ); document.write( "replace x with 2, in the original problem:
\n" ); document.write( "ln(2-1) + ln(6) = ln(2*3)
\n" ); document.write( "of course the ln of 1 is 0, so it checks out
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