document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=688515>Question 688515</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For the equation of the parabola find the coordinates for the VERTEX, FOCUS and the equations of the DIRECTRIX AND AXIS OF SYMMETRY <BR>\n" );
document.write( "Y^2+6y+9=12-12x\r<BR>\n" );
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document.write( "Please help I've been working on it for an hour now.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #425761 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=425761\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For the equation of the parabola find the coordinates for the VERTEX, FOCUS and the equations of the DIRECTRIX AND AXIS OF SYMMETRY <BR>\n" );
document.write( "Y^2+6y+9=12-12x<BR>\n" );
document.write( "(Y^2+6y+9)=12-12x-9+9<BR>\n" );
document.write( "(y+3)^2=12-12x=12(1-x)=-12(x-1)<BR>\n" );
document.write( "(y+3)^2=-12(x-1)<BR>\n" );
document.write( "This is an equation of a parabola that opens leftwards<BR>\n" );
document.write( "Its standard form: (y-k)^2=-4p(x-h), (h,k)=(x,y) coordinates of the vertex<BR>\n" );
document.write( "For given parabola:<BR>\n" );
document.write( "vertex: (1,-3)<BR>\n" );
document.write( "axis of symmetry: y=-3<BR>\n" );
document.write( "4p=12<BR>\n" );
document.write( "p=3<BR>\n" );
document.write( "focus: (-2,-3) (p-distance to the left of the vertex on the axis of symmetry)<BR>\n" );
document.write( "directrix: x=4 (p-distance to the right of the vertex on the axis of symmetry) </SPAN>\n" );
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