document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=61847>Question 61847</A>: <I><SPAN STYLE=\"word-break: break-all;\"> It is 2:07 AM and I am fried.  Please help.\r<BR>\n" );
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document.write( "Solve by the addition method\r<BR>\n" );
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document.write( "5x -3y= -20<BR>\n" );
document.write( "3x + 2y= 7\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #42571 by </B><A HREF=/tutors/aboutme.mpl?userid=uma><B>uma(370)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uma><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=42571\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  5x - 3y = - 20  ---------------(1)<BR>\n" );
document.write( " 3x + 2y = 7    -----------------(20\r<BR>\n" );
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document.write( "(1) x 2 gives  10x - 6y = - 40\r<BR>\n" );
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document.write( "(2) x 3 gives  9x + 6y = 21\r<BR>\n" );
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document.write( "Adding the above we get..<BR>\n" );
document.write( "19x = - 19<BR>\n" );
document.write( "==> 19x/19 = - 19/19<BR>\n" );
document.write( "==> x = - 1\r<BR>\n" );
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document.write( "Plugging in x =  -1 in (2)...<BR>\n" );
document.write( "3(-1) + 2y = 7<BR>\n" );
document.write( "==> -3 + 2y = 7<BR>\n" );
document.write( "==> 2y = 7 + 3  [adding 3 to both the sides of the equation]\r<BR>\n" );
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document.write( "==> 2y = 10<BR>\n" );
document.write( "==> 2y/2 = 10/2<BR>\n" );
document.write( "==> y = 5\r<BR>\n" );
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document.write( "Thus x = -1,   y = 5\r<BR>\n" );
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document.write( "Good Luck!!! </SPAN>\n" );
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