document.write( "Question 688822: How many gallons of a 30% acid solution must be mixed with 20 gallons of a 19% solution to obtain a solution that is 25% acid? \n" ); document.write( "
Algebra.Com's Answer #425703 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=amount of 30% solution needed\r \n" ); document.write( "\n" ); document.write( "Now we know that the amount of pure acid that exists before the mixture takes place (0.30x+0.19*20) has to equal the amount of pure acid that exists after the mixture takes place(0.25(20+x)). Sooooooo \n" ); document.write( "0.30x+0.19*20=0.25(20+x) \n" ); document.write( "0.30x+3.8=5+0.25x subtract 0.25x and also 3.8 from each side \n" ); document.write( "0.05x=1.2 \n" ); document.write( "x=24 gal---amount of 30% acid solution needed \n" ); document.write( "CK \n" ); document.write( "0.30*24+3.8=0.25*44 \n" ); document.write( "7.2+3.8=11 \n" ); document.write( "11=11\r \n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor \n" ); document.write( " |