document.write( "Question 688211: How do I put the equation in standard form? The vertices and the center of the equation are also needed: \r
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document.write( "-16x^2 - 4y^2 = 48x - 20y + 57 \r
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document.write( "I did try to solve it using completing the square but it didn't work out the correct way, because the numbers I came up with I was not able to factor them. \n" );
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Algebra.Com's Answer #425702 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! How do I put the equation in standard form? The vertices and the center of the equation are also needed: \n" ); document.write( "-16x^2 - 4y^2 = 48x - 20y + 57 \n" ); document.write( "-16x^2 - 4y^2 = 48x - 20y + 57 \n" ); document.write( "16x^2+48x+4y^2-20y=-57 \n" ); document.write( "complete the square \n" ); document.write( "16(x^2+3x+9/4)+4(y^2-5y+25/4=-57+36+25 \n" ); document.write( "16(x+3/2)^2+4(y+5/2)^2=4 \n" ); document.write( " \n" ); document.write( "This is an equation of an ellipse with vertical major axis. \n" ); document.write( "Its standard form: \n" ); document.write( "center: (-3/2,5/2) \n" ); document.write( "a^2=1 \n" ); document.write( "a=1 \n" ); document.write( "vertices=(-3/2,5/2±a)=(-3/2,5/2±1)=(-3/2,3/2) and (-3/2,7/2) \n" ); document.write( " |