document.write( "Question 688211: How do I put the equation in standard form? The vertices and the center of the equation are also needed: \r
\n" ); document.write( "\n" ); document.write( "-16x^2 - 4y^2 = 48x - 20y + 57 \r
\n" ); document.write( "\n" ); document.write( "I did try to solve it using completing the square but it didn't work out the correct way, because the numbers I came up with I was not able to factor them.
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Algebra.Com's Answer #425702 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
How do I put the equation in standard form? The vertices and the center of the equation are also needed:
\n" ); document.write( "-16x^2 - 4y^2 = 48x - 20y + 57
\n" ); document.write( "-16x^2 - 4y^2 = 48x - 20y + 57
\n" ); document.write( "16x^2+48x+4y^2-20y=-57
\n" ); document.write( "complete the square
\n" ); document.write( "16(x^2+3x+9/4)+4(y^2-5y+25/4=-57+36+25
\n" ); document.write( "16(x+3/2)^2+4(y+5/2)^2=4
\n" ); document.write( "\"4%28x%2B3%2F2%29%5E2%2B%28y-5%2F2%29%5E2=1\"
\n" ); document.write( "This is an equation of an ellipse with vertical major axis.
\n" ); document.write( "Its standard form:\"%28x-h%29%5E2%2Fb%5E2%2B%28y-k%29%5E2%2Fa%5E2=1\",a>b, (h,k)=(x,y) coordinates of center
\n" ); document.write( "center: (-3/2,5/2)
\n" ); document.write( "a^2=1
\n" ); document.write( "a=1
\n" ); document.write( "vertices=(-3/2,5/2±a)=(-3/2,5/2±1)=(-3/2,3/2) and (-3/2,7/2)
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