document.write( "Question 688745: The sum of the area of two squares is 89 squares centimeters. The lenght of a side of the larger square is 3 cm more than the lenght of a side of the smaller square. Find the dimensions of each square. \n" ); document.write( "
Algebra.Com's Answer #425682 by Stitch(470)\"\" \"About 
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Let X = the length of a side on the small square.
\n" ); document.write( "Let Y = the length of a side on the large square.\r
\n" ); document.write( "\n" ); document.write( "The area of a square is the Length^2\r
\n" ); document.write( "\n" ); document.write( "Equation 1: \"X%5E2+%2B+Y%5E2+=+89\"
\n" ); document.write( "Equation 2: \"X+%2B+3+=+Y\"
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\n" ); document.write( "Substitute (X + 3) into equation 1 for Y.
\n" ); document.write( "Equation 1: \"X%5E2+%2B+Y%5E2+=+89\"
\n" ); document.write( "\"X%5E2+%2B+%28X+%2B+3%29%5E2+=+89\"
\n" ); document.write( "Rewrite the equation
\n" ); document.write( "\"X%5E2+%2B+%28X%2B3%29%2A%28X%2B3%29+=+89\"
\n" ); document.write( "Simplify the equation
\n" ); document.write( "\"X%5E2+%2B+X%5E2+%2B+3X+%2B+3X+%2B+9+=+89\"
\n" ); document.write( "Combine like terms
\n" ); document.write( "\"2X%5E2+%2B+6X+%2B+9+=+89\"
\n" ); document.write( "Subtract 89 from bith sides
\n" ); document.write( "\"2X%5E2+%2B+6X+-+80+=+0\"
\n" ); document.write( "Use the quadratic equation.\r
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"aX%5E2%2BbX%2Bc=0\" (in our case \"2X%5E2%2B6X%2B-80+=+0\") has the following solutons:
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\n" ); document.write( " \"X%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%286%29%5E2-4%2A2%2A-80=676\".
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\n" ); document.write( " Discriminant d=676 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-6%2B-sqrt%28+676+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"X%5B1%5D+=+%28-%286%29%2Bsqrt%28+676+%29%29%2F2%5C2+=+5\"
\n" ); document.write( " \"X%5B2%5D+=+%28-%286%29-sqrt%28+676+%29%29%2F2%5C2+=+-8\"
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\n" ); document.write( " Quadratic expression \"2X%5E2%2B6X%2B-80\" can be factored:
\n" ); document.write( " \"2X%5E2%2B6X%2B-80+=+2%28X-5%29%2A%28X--8%29\"
\n" ); document.write( " Again, the answer is: 5, -8.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+2%2Ax%5E2%2B6%2Ax%2B-80+%29\"

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\n" ); document.write( "\n" ); document.write( "Note that you can not have a negative value for the answer. So X = 5
\n" ); document.write( "Now plug 5 into equation 2 for X
\n" ); document.write( "Equation 2: \"X+%2B+3+=+Y\"
\n" ); document.write( "\"5+%2B+3+=+Y\"
\n" ); document.write( "\"highlight%288+=+Y%29\"\r
\n" ); document.write( "\n" ); document.write( "So the two sides are 5cm & 8cm
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