document.write( "Question 688745: The sum of the area of two squares is 89 squares centimeters. The lenght of a side of the larger square is 3 cm more than the lenght of a side of the smaller square. Find the dimensions of each square. \n" ); document.write( "
Algebra.Com's Answer #425682 by Stitch(470)![]() ![]() ![]() You can put this solution on YOUR website! Let X = the length of a side on the small square. \n" ); document.write( "Let Y = the length of a side on the large square.\r \n" ); document.write( "\n" ); document.write( "The area of a square is the Length^2\r \n" ); document.write( "\n" ); document.write( "Equation 1: \n" ); document.write( "Equation 2: \n" ); document.write( "---------------------------------- \n" ); document.write( "Substitute (X + 3) into equation 1 for Y. \n" ); document.write( "Equation 1: \n" ); document.write( " \n" ); document.write( "Rewrite the equation \n" ); document.write( " \n" ); document.write( "Simplify the equation \n" ); document.write( " \n" ); document.write( "Combine like terms \n" ); document.write( " \n" ); document.write( "Subtract 89 from bith sides \n" ); document.write( " \n" ); document.write( "Use the quadratic equation.\r \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note that you can not have a negative value for the answer. So X = 5 \n" ); document.write( "Now plug 5 into equation 2 for X \n" ); document.write( "Equation 2: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the two sides are 5cm & 8cm \n" ); document.write( " \n" ); document.write( " |